The Elsmar Cove Forum How to Calculate the Area under the Normal Distribution Curve
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#1
13th October 2006, 12:16 AM
 Sushil Kumar Involved - Posts   Registration Date: Nov 2004 Location: Haryana (India) Age: 40 Posts: 50 Thanks Given to Others: 0 Thanked 52 Times in 7 Posts Karma Power: 41 Karma: 531
How to Calculate the Area under the Normal Distribution Curve

Hello,
Can any one provide solution of the following question?

In a normal distribution with mean 2.0 and standard deviation 0.05, what is the area under the curve between 1.99 & 2.10 standard deviation units? Show the calculations.

#2
13th October 2006, 01:23 AM
 alokb Involved in Discussions   Registration Date: Sep 2005 Location: India Age: 53 Posts: 21 Thanks Given to Others: 1 Thanked 5 Times in 5 Posts Karma Power: 34 Karma: 35
Re: how to calculate area under curve

Dear Sir,

thanks,
Alok

PS:Pl forgive the quality of rough sketch .
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 Area under the currve.doc (26.5 KB, 380 views)
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#3
13th October 2006, 06:27 AM
 Atul Khandekar Forum Administrator   Registration Date: Mar 2000 Location: Pune, India Age: 50 Posts: 1,321 Thanks Given to Others: 155 Thanked 204 Times in 141 Posts Karma Power: 400
Re: how to calculate area under curve

An easy to follow explanation can be found here.

Instead of z-tables you can use the Excel NORMDIST function.
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#4
14th October 2006, 02:17 AM
 Sushil Kumar Involved - Posts   Registration Date: Nov 2004 Location: Haryana (India) Age: 40 Posts: 50 Thanks Given to Others: 0 Thanked 52 Times in 7 Posts Karma Power: 41 Karma: 531
Re: How to Calculate the Area under the Normal Distribution Curve

Dear Mr Alok & Mr Atul,
I am very very thankful to you as u have cleared the concept to me. I always feel confused myself on this subject.

Sir, I have made minor change in solution for my easy understanding
Area under the curve

Z1 = 2.10-2.00 = 2
0.05
Z2 = 1.99-2.00 = -0.2
0.05

Total area covered by Z1 = 0.977249938

Total area covered by Z2 = 1- 0.579259687 =0.420740313

Intercepted area between Z1 and Z2 = 0.977249938 – 0.420740313= 0.556509625

OR

Intercepted area between Z1 and Z2 = 1-( Z1 + Z2)
1-(0.977249938+0.579259687)= 0.556509625

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