C
convivial
I would like to know the reliability of 20 samples. Assume there is no failure:
Reliability R(t) = ?
Confidence Level P = 80% (in every case)
Required test duration = 100 hours
Weibull paramete b = 2 (always remains 2)
I know I can use this formula: R(t) = (1 - P)^(1/(L)^b.n) where L = life time ratio
But before applying this formula I divide these 20 samples in to two groups having 10 samples each.
For first group (10 samples) I take Lifetime ratio (L) = 0.7, I apply the above formula and get R(t) = 65% (say)
For Second group (10 samples) I take Lifetime ratio (L) = 1.3, I apply the above formula and get R(t) = 70% (say)
Now I have got two reliabilities for these 2 groups. Can I combine these two reliabilities to get a final reliability? If yes, then how shall I combine these two? Shall I multiply or simple add these two?
Reliability R(t) = ?
Confidence Level P = 80% (in every case)
Required test duration = 100 hours
Weibull paramete b = 2 (always remains 2)
I know I can use this formula: R(t) = (1 - P)^(1/(L)^b.n) where L = life time ratio
But before applying this formula I divide these 20 samples in to two groups having 10 samples each.
For first group (10 samples) I take Lifetime ratio (L) = 0.7, I apply the above formula and get R(t) = 65% (say)
For Second group (10 samples) I take Lifetime ratio (L) = 1.3, I apply the above formula and get R(t) = 70% (say)
Now I have got two reliabilities for these 2 groups. Can I combine these two reliabilities to get a final reliability? If yes, then how shall I combine these two? Shall I multiply or simple add these two?
Last edited by a moderator: