We are designing a class I ME equipment. We used a standard IEC 60601-1 AC/DC with the secondary circuit totally earthed. Our SIP/SOP is a USB 3.0 port on the secondary side. We did not apply extra isolation method on this SIP/SOP.
According to Fig. J.4 in IEC 60601-1 3.1, the isulation between the mains part and SIP/SOP should be 2 MOOP.
As a result, if we apply a 3000 V a.c. test voltage between the mains and the SIP/SOP, the test will fail. The reason is obvious. The insulation of a standard medical grade AC/DC between the mains part and the earth is larger than 1500 V but smaller than 3000 V. If a 3000 V a.c. test voltage is applied between the mains and the SIP/SOP, there will be (AC coupled) leakage along mains, earth, and SIP/SOP (USB 3.0) circuits.
Do we really perform this 3000 V a.c. test? We think a 1500-V insulation between mains and earth plus secondary circuit earthing are enough to provide a 2 MOOP, and the test voltage should be reduced to 1500 V a.c. (Table 6).
Am I correct about this understanding of 2 MOOP?
According to Fig. J.4 in IEC 60601-1 3.1, the isulation between the mains part and SIP/SOP should be 2 MOOP.
As a result, if we apply a 3000 V a.c. test voltage between the mains and the SIP/SOP, the test will fail. The reason is obvious. The insulation of a standard medical grade AC/DC between the mains part and the earth is larger than 1500 V but smaller than 3000 V. If a 3000 V a.c. test voltage is applied between the mains and the SIP/SOP, there will be (AC coupled) leakage along mains, earth, and SIP/SOP (USB 3.0) circuits.
Do we really perform this 3000 V a.c. test? We think a 1500-V insulation between mains and earth plus secondary circuit earthing are enough to provide a 2 MOOP, and the test voltage should be reduced to 1500 V a.c. (Table 6).
Am I correct about this understanding of 2 MOOP?