F
Fred1977
Hi All,
I'm working on a medical device and am a bit lost at sea as to whether isolation is required or not. The device consists of a small desktop unit with TFT display, buttons and USB socket for PC connect. The desktop unit is battery powered (4x1.5V), or can get 5V from USB. A doppler ultrasound probe (huntleigh) is plugged into the desktop unit via a cable. Typically the operator holds the probe against patients neck for about 30 seconds at a time to capture a signal.
The device presently contains no isolation. I gather the probe can be classified as a type B applied part, and in 60601-1 2006 I read this:
8.5.2.2 Type B applied parts:
...Type B part that is NOT protectively earthed shall be seperated by one MOPP from metal accessible parts that are nont protecticely earthed, unless:
- Metal accesible part is physically contiguous with applied part, or
- the risk that the metal accesible part will make contact with a source of voltage or leakage current above permitted limits is acceptably low.
Does the PC connection mean quite high leakage current is possible, and thus neither exclusion paragraph applies and I need that one MOPP isolation? From some reading I gather the USB port already offers one MOPP, in which case I would need no further isolation... but I am not certain that the 'PC USB port already offers one MOPP' statement is true or not.
Secondly, if I read further into the 'components and wiring' section, I find this:
8.10.4.1 Limitation of operating voltages:
Cord-connected hand held control devices of ME equipment and their associated cords shall contain only conductors operating at voltages =< 60Vdc, in circuits isolated from MAINS part by two MOPPs.
In the case of the above, does this mean I need two MOPPS? I would think that the doppler probe is not a 'hand held control', or is it? If this paragraph does apply to me, it just leads to more questions. The doppler probe itself allegedly includes 1 MOPP of seperation by virtue of its plastic casing design (I am awaiting confirmation from Huntleigh), in which case if the probe has a MOPP, and the PC USB port already offers a MOPP, I might be safe.. however the above paragraph says the conductors within the cord are also subjkect to the 2 MOPPs isolation, which means I need to isolate the doppler inside my desktop case housing.
Any guidance will be most appreciated, I fail to see any risk in the product's current un-isolated configuration, and would hate to have to add layers of expensive isolation if I don't need to.
Many thanks!
I'm working on a medical device and am a bit lost at sea as to whether isolation is required or not. The device consists of a small desktop unit with TFT display, buttons and USB socket for PC connect. The desktop unit is battery powered (4x1.5V), or can get 5V from USB. A doppler ultrasound probe (huntleigh) is plugged into the desktop unit via a cable. Typically the operator holds the probe against patients neck for about 30 seconds at a time to capture a signal.
The device presently contains no isolation. I gather the probe can be classified as a type B applied part, and in 60601-1 2006 I read this:
8.5.2.2 Type B applied parts:
...Type B part that is NOT protectively earthed shall be seperated by one MOPP from metal accessible parts that are nont protecticely earthed, unless:
- Metal accesible part is physically contiguous with applied part, or
- the risk that the metal accesible part will make contact with a source of voltage or leakage current above permitted limits is acceptably low.
Does the PC connection mean quite high leakage current is possible, and thus neither exclusion paragraph applies and I need that one MOPP isolation? From some reading I gather the USB port already offers one MOPP, in which case I would need no further isolation... but I am not certain that the 'PC USB port already offers one MOPP' statement is true or not.
Secondly, if I read further into the 'components and wiring' section, I find this:
8.10.4.1 Limitation of operating voltages:
Cord-connected hand held control devices of ME equipment and their associated cords shall contain only conductors operating at voltages =< 60Vdc, in circuits isolated from MAINS part by two MOPPs.
In the case of the above, does this mean I need two MOPPS? I would think that the doppler probe is not a 'hand held control', or is it? If this paragraph does apply to me, it just leads to more questions. The doppler probe itself allegedly includes 1 MOPP of seperation by virtue of its plastic casing design (I am awaiting confirmation from Huntleigh), in which case if the probe has a MOPP, and the PC USB port already offers a MOPP, I might be safe.. however the above paragraph says the conductors within the cord are also subjkect to the 2 MOPPs isolation, which means I need to isolate the doppler inside my desktop case housing.
Any guidance will be most appreciated, I fail to see any risk in the product's current un-isolated configuration, and would hate to have to add layers of expensive isolation if I don't need to.
Many thanks!