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Here is what ASME Y14.5M-1994 says...
1.6.1(a) Where the dimensions is less hthan one millimeter, a zero precedres the decimal point.
1.6.1(b) Where the dimension is a whole number, neither the decimal point nor a zero is shown.
1.6.2(a) A zero is not used before the decimal point for values of less than one inch.
1.6.2(b) A dimension is expressed to the sam number of decimal places as its tolerance.
Now heres my question.
If my engineers put say 1.240-1.260" on a drawing, and my inspectors come in and measure that dimension but measure to 1.26005, it's technically a nonconforming part. According to the standard they should not even be measuring to that accuracy, am I correct?
This question is raised because of a class I attended with Pratt and Whitney, and they require absolute measurments. Basically what they have said is if our drawing is labeled as .000" then we want to see an inspection report with .XXX" and not .XXXX".
Am I getting this right or am I off base?
1.6.1(a) Where the dimensions is less hthan one millimeter, a zero precedres the decimal point.
1.6.1(b) Where the dimension is a whole number, neither the decimal point nor a zero is shown.
1.6.2(a) A zero is not used before the decimal point for values of less than one inch.
1.6.2(b) A dimension is expressed to the sam number of decimal places as its tolerance.
Now heres my question.
If my engineers put say 1.240-1.260" on a drawing, and my inspectors come in and measure that dimension but measure to 1.26005, it's technically a nonconforming part. According to the standard they should not even be measuring to that accuracy, am I correct?
This question is raised because of a class I attended with Pratt and Whitney, and they require absolute measurments. Basically what they have said is if our drawing is labeled as .000" then we want to see an inspection report with .XXX" and not .XXXX".
Am I getting this right or am I off base?
