A
Dear fellows,
I am trying to make all linearity calculations and I am using the "MSA 3rd Linearity Example.xls" as my guide.
Could anyone that already did the same help with the following doubt in the confidence level limits formula?
The formula has (inside a square root) a ratio:
(x0-xbar)^2 / sum[(xi-xbar)^2]
but in the excel file it is used the following ratio:
(x0-xbar)^2 / {sum[(xi-xbar)^2]*m}
where the quantity "{sum[(xi-xbar)^2]*m}" is called "sumsq-all" (at C32 cell)
What is the reason of this difference? From where comes the "*m"? Is MSA formula wrong (again!)?
Thanks in advance!
Alexandre Bonatto
I am trying to make all linearity calculations and I am using the "MSA 3rd Linearity Example.xls" as my guide.
Could anyone that already did the same help with the following doubt in the confidence level limits formula?
The formula has (inside a square root) a ratio:
(x0-xbar)^2 / sum[(xi-xbar)^2]
but in the excel file it is used the following ratio:
(x0-xbar)^2 / {sum[(xi-xbar)^2]*m}
where the quantity "{sum[(xi-xbar)^2]*m}" is called "sumsq-all" (at C32 cell)
What is the reason of this difference? From where comes the "*m"? Is MSA formula wrong (again!)?
Thanks in advance!
Alexandre Bonatto