Proud Liberal
Quite Involved in Discussions
I work in a plastic profile extrusion company that routinely deals with part bow. Our customers generally give us a specification for the entire length of the part.
Historically, parts were checked with pin gages being slid under the bow with the part on a surface plate or between two parts placed back to back. Both of these methods were ripe with error due to the "feel" required by the operator.
I designed and built a 12" fixture that is used on a optical comparator that eliminates the "feel" and increases the measurement resolution from .xxx" to .xxxx". The only problem was converting from bow/ft to overall bow specifications. To deal with that, we us a spreadsheet that:
• converts the bow (distance from the 12" cord to the high point of the arc/tangent) into the corresponding radius,
• then caculated the bow in THAT radius with a cord length = part length.
Our customer cites from GEOMETRICS by Lowell Foster the section on composite straightness. The example listed shows a straightness callout of .005" per 1.000" and the composite tolerance of .020" on part with a length of 4.00". Since the part just happens to be 4", their contention is that the .020" tolerance is calculated by multiplying the tolerance per inch by the length divided by per units measure (inches in this case).
I think that the example is an unforturnate carry over from the example in the ANSI DIMENSIONING & TOLERANCING Y14.5M standard where the math just happens to work our that way. But the standard goes further in §6.4.1.4 and explains:
"Caution should be exercised when using unit control without specigyina a maximum limit because of the relatively large throretical variations that may result if left unrestricted. If the unit variation apprears as a "bow" is allowed to continue at the same rate for several units, the overall tolerance variation may result in an unsatisfactory part."
The customer agrees this is an issue but contends that the second callout is unnecessary because of the example in the book. NOTE: see attached file for images from GEOMETRICS and ANSI Y14.5M.
I think that if the example would have been of a 96.850" part with a .002" per foot straightness and .020" overall tolerances, this confusion would have been eliminated since the overall tolerance wasn't .0161" (.002 x [96.850/12]).
I hope this isn't totally confusing.
Now, to my point. Which interpretation is correct? I have no problem either way but need a clarification for internal training purposed.
Historically, parts were checked with pin gages being slid under the bow with the part on a surface plate or between two parts placed back to back. Both of these methods were ripe with error due to the "feel" required by the operator.
I designed and built a 12" fixture that is used on a optical comparator that eliminates the "feel" and increases the measurement resolution from .xxx" to .xxxx". The only problem was converting from bow/ft to overall bow specifications. To deal with that, we us a spreadsheet that:
• converts the bow (distance from the 12" cord to the high point of the arc/tangent) into the corresponding radius,
• then caculated the bow in THAT radius with a cord length = part length.
Our customer cites from GEOMETRICS by Lowell Foster the section on composite straightness. The example listed shows a straightness callout of .005" per 1.000" and the composite tolerance of .020" on part with a length of 4.00". Since the part just happens to be 4", their contention is that the .020" tolerance is calculated by multiplying the tolerance per inch by the length divided by per units measure (inches in this case).
I think that the example is an unforturnate carry over from the example in the ANSI DIMENSIONING & TOLERANCING Y14.5M standard where the math just happens to work our that way. But the standard goes further in §6.4.1.4 and explains:
"Caution should be exercised when using unit control without specigyina a maximum limit because of the relatively large throretical variations that may result if left unrestricted. If the unit variation apprears as a "bow" is allowed to continue at the same rate for several units, the overall tolerance variation may result in an unsatisfactory part."
The customer agrees this is an issue but contends that the second callout is unnecessary because of the example in the book. NOTE: see attached file for images from GEOMETRICS and ANSI Y14.5M.
I think that if the example would have been of a 96.850" part with a .002" per foot straightness and .020" overall tolerances, this confusion would have been eliminated since the overall tolerance wasn't .0161" (.002 x [96.850/12]).
I hope this isn't totally confusing.
Now, to my point. Which interpretation is correct? I have no problem either way but need a clarification for internal training purposed.