Re: GD&T basic question
Thank you Michael. Appreciate your help.
The first TP Dia 0.395" -0.384", I think I can get center of Cir 1.812 (Plant A) to be (0,0), compare the center of this small Cir 0.390", use square root method to calculate the error, such as Squ((x-0.390)2+(y-0.390)2).
The second TP0.250 will be the same idea, with position of center line of the notch. It will be (w-0.250)
The third TP 0.148", is that the position of center of hole 0.148" ( M, N), then I use squ((M-0.148)2+(N-0.148))?
Thank you,
Emma