Good Day To All Covers,
I found a similar thread, although it did not totally answer my question.
I am testing two verification runs of an improved process, part of a Six Sigma project, the two verification runs are 30 pieces each; the First involves machine crimped wire/terminal connections. The Second 30 pieces are the same wire terminal combination, however they are hand crimped.
I am testing the Tensile Strength using a digital force meter; finally the questions, I wish to test for differences in mean between the two samples.
First I check for or assess the distribution of each sample. The first sample is not normal, rather Weibull; the second is normal.
When testing the two samples for equal variance (f-test) it passes both the f-test statistic/p-value and the Levene's for non-normal....therefore it passes test for equal variance.
How does one test for mean differences between one Weibull distribution and a normal distribution?
Is normalcy a concern when running T-tests or ANOVA for matter??
Thank you for your assistance...
Regards,
Marty
I found a similar thread, although it did not totally answer my question.
I am testing two verification runs of an improved process, part of a Six Sigma project, the two verification runs are 30 pieces each; the First involves machine crimped wire/terminal connections. The Second 30 pieces are the same wire terminal combination, however they are hand crimped.
I am testing the Tensile Strength using a digital force meter; finally the questions, I wish to test for differences in mean between the two samples.
First I check for or assess the distribution of each sample. The first sample is not normal, rather Weibull; the second is normal.
When testing the two samples for equal variance (f-test) it passes both the f-test statistic/p-value and the Levene's for non-normal....therefore it passes test for equal variance.
How does one test for mean differences between one Weibull distribution and a normal distribution?
Is normalcy a concern when running T-tests or ANOVA for matter??
Thank you for your assistance...
Regards,
Marty