E
enjoyneer
hi ...below some data is given please help me in interpreting......
no of cases analysed are 14.....
Regression Analysis: RI versus Fe(T), %FeO, ...
The regression equation is
RI = 350 - 3.91 Fe(T) - 2.18 %FeO - 4.63 %MgO - 307 %K2O - 172 %P
+ 4.24 Basicity - 0.910 MPS
Predictor Coef SE coef T P VIF
Constant 349.87 45.35 7.72 0.000
Fe(T) -3.9053 0.5386 -7.25 0.000 3.181
%FeO -2.1818 0.4434 -4.92 0.003 2.334
%MgO -4.626 1.791 -2.58 0.042 2.459
%K2O -306.91 49.69 -6.18 0.001 4.061
%P -172.18 67.17 -2.56 0.043 4.728
Basicity 4.240 3.127 1.36 0.224 4.300
MPS -0.9102 0.3350 -2.72 0.035 1.268
S = 0.802628 R-Sq = 97.5% R-Sq(adj) = 94.5%
PRESS = 17.8900 R-Sq(pred) = 88.30%
Analysis of Variance
Source DF SS MS F P
Regression 7 149.020 21.289 33.05 0.000
Residual Error 6 3.865 0.644
Total 13 152.886
There are no replicates.
Minitab cannot do the lack of fit test based on pure error.
Source DF Seq SS
Fe(T) 1 9.016
%FeO 1 30.366
%MgO 1 0.612
%K2O 1 71.800
%P 1 31.370
Basicity 1 1.100
MPS 1 4.756
Unusual Observations
Obs Fe(T) RI Fit SE Fit Residual St Resid
4 56.3 45.620 44.627 0.639 0.993 2.05R
R denotes an observation with a large standardized residual.
please also tell me the correct approach if you have any...........
no of cases analysed are 14.....
Regression Analysis: RI versus Fe(T), %FeO, ...
The regression equation is
RI = 350 - 3.91 Fe(T) - 2.18 %FeO - 4.63 %MgO - 307 %K2O - 172 %P
+ 4.24 Basicity - 0.910 MPS
Predictor Coef SE coef T P VIF
Constant 349.87 45.35 7.72 0.000
Fe(T) -3.9053 0.5386 -7.25 0.000 3.181
%FeO -2.1818 0.4434 -4.92 0.003 2.334
%MgO -4.626 1.791 -2.58 0.042 2.459
%K2O -306.91 49.69 -6.18 0.001 4.061
%P -172.18 67.17 -2.56 0.043 4.728
Basicity 4.240 3.127 1.36 0.224 4.300
MPS -0.9102 0.3350 -2.72 0.035 1.268
S = 0.802628 R-Sq = 97.5% R-Sq(adj) = 94.5%
PRESS = 17.8900 R-Sq(pred) = 88.30%
Analysis of Variance
Source DF SS MS F P
Regression 7 149.020 21.289 33.05 0.000
Residual Error 6 3.865 0.644
Total 13 152.886
There are no replicates.
Minitab cannot do the lack of fit test based on pure error.
Source DF Seq SS
Fe(T) 1 9.016
%FeO 1 30.366
%MgO 1 0.612
%K2O 1 71.800
%P 1 31.370
Basicity 1 1.100
MPS 1 4.756
Unusual Observations
Obs Fe(T) RI Fit SE Fit Residual St Resid
4 56.3 45.620 44.627 0.639 0.993 2.05R
R denotes an observation with a large standardized residual.
please also tell me the correct approach if you have any...........
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