Another mathematical riddle

[abelardo]

You must cut a birthday cake into exactly eight pieces, but you're only allowed to make three straight cuts, and you can't move pieces of the cake as you cut. How can you do it?

 

[Phiobi]

Cut across the dia (creates 2 bits of cake) then again at 90 deg to the first cut (creates 4 bits of cake), then (hard to explain) section through 90 deg the original cuts (creates 8 bits of cake)

Make sense?

 

[Qualqueen]

Phiobi,

That's only 6 pieces!!!!

 

[Phiobi]

Its not....
If the the "height" of the cake is Z and you have X and Y
0,0,0 is the middle bottom of the cake then you cut across the dia crossing 0,0,0 then again at 90 degrees to that.... this gives you 4 bits.... then, say the cake is 50mm high (Z) then half rotate the knife 90 deg to the original cuts and pass through X0 Y0 Z25 this doubles the number of bits you have to 8

Thats what I was trying to say!

 

[Qualqueen]

gotcha. Didn't think x,y and ZZZZZZZZZZZZZ

 

[Polly Pure Bread]

You must cut a birthday cake into exactly eight pieces, but you're only allowed to make three straight cuts, and you can't move pieces of the cake as you cut. How can you do it?

What’s the shape of the cake? Is it round, square, rectangle or triangle?

 

[Polly Pure Bread]

The first 2 slices is vertical but an ‘X’ cut across the cake = 4 slices
3rd slice is horizontal = 4x2=8 slices