From the information posted above...
The thrust link in question transfers thrust from the engine to the airframe.... there are two, one for redundancy in case one were to fail.
Makes me wonder...... if there are two, are they normally sharing the load, otherwise if one breaks (the one taking the full load) how is the full load transferred to the other one? If the load is normally shared between the two thrust links and one breaks, then the other is suddenly taking twice its normal load (and hence may be more prone to failure too?). There must be more to this than meets the eye, so to speak
In general engineering terms (and I'm no aircraft engineer, just a run-of-the-mill mech eng by training), this is not how redundancy is supposed to work. Redundancy would mean
each would be designed to carry the entire load on its own, and then some (safety factoring). So in theory it should be able to survive the loss of its mate. Yes, there might be a shock effect due to the sudden increase in load (going from about half the load, in this case, to full load), but I'd expect the esteemed aircraft design engineers to account for that, too.
The main issue (in general) is accurately identifying the "real" nominal load (against which redundancy is applied). Obviously, not a simple task at all, in any critical-function engineering design job. If the nominated design load + applied safety factors deviate vastly from the actual loads (+ any effects not accounted for), redundancy might hide the deficiency for a while, and then, when one of the redundant members fails (for whatever reason - could e.g. be a microscopic manufacturing flaw), catastrophic failure of the entire set might soon follow.